
Character Frequency Analysis: A Python Problem Breakdown
Sep 15
1 min read
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The Problem
The HackerRank "Company Logo" problem asks you to find the three most frequent characters in a string, with alphabetical ordering as a tiebreaker. Here's one approach to solving it:
s = input()
slist = []
sdictionary = {}
for letter in s:
slist.append(letter)
for letter in slist:
if letter not in sdictionary.keys():
sdictionary[letter] = 0
if letter in sdictionary.keys():
sdictionary[letter] = sdictionary[letter] + 1
sorted_items = sorted(sdictionary.items(), key=lambda x: (-x[1], x[0]))
for i in range(min(3, len(sorted_items))):
key, value = sorted_items[i]
print(f"{key} {value}")
How It Works
Step 1: Convert to list The code converts the input string to a list of characters. While strings are already iterable in Python, this makes the intent clear.
Step 2: Count frequencies Each character is checked against the dictionary. If it's new, it gets initialized to 0, then incremented. This ensures every character gets counted properly.
Step 3: Sort by criteria The sorting line does two things:
-x[1] sorts by frequency in descending order
x[0] sorts alphabetically for ties
Step 4: Print results Uses min(3, len(sorted_items)) to handle cases where there are fewer than 3 unique characters.
Why This Problem Matters
Character frequency analysis appears in:
Text processing and analysis
Compression algorithms
Cryptography
Data validation





